3.34 \(\int \frac{(a+b x^3)^{7/3}}{a-b x^3} \, dx\)

Optimal. Leaf size=483 \[ -\frac{7 a^2 x \left (\frac{b x^3}{a}+1\right )^{2/3} \, _2F_1\left (\frac{1}{3},\frac{2}{3};\frac{4}{3};-\frac{b x^3}{a}\right )}{5 \left (a+b x^3\right )^{2/3}}-\frac{2 \sqrt [3]{2} a^{5/3} \log \left (2^{2/3}-\frac{\sqrt [3]{a}+\sqrt [3]{b} x}{\sqrt [3]{a+b x^3}}\right )}{3 \sqrt [3]{b}}+\frac{2 \sqrt [3]{2} a^{5/3} \log \left (\frac{2^{2/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )^2}{\left (a+b x^3\right )^{2/3}}-\frac{\sqrt [3]{2} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{a+b x^3}}+1\right )}{3 \sqrt [3]{b}}-\frac{4 \sqrt [3]{2} a^{5/3} \log \left (\frac{\sqrt [3]{2} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{a+b x^3}}+1\right )}{3 \sqrt [3]{b}}+\frac{\sqrt [3]{2} a^{5/3} \log \left (\frac{\left (\sqrt [3]{a}+\sqrt [3]{b} x\right )^2}{\left (a+b x^3\right )^{2/3}}+\frac{2^{2/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{a+b x^3}}+2 \sqrt [3]{2}\right )}{3 \sqrt [3]{b}}-\frac{4 \sqrt [3]{2} a^{5/3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{2} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{a+b x^3}}}{\sqrt{3}}\right )}{\sqrt{3} \sqrt [3]{b}}-\frac{2 \sqrt [3]{2} a^{5/3} \tan ^{-1}\left (\frac{\frac{\sqrt [3]{2} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{a+b x^3}}+1}{\sqrt{3}}\right )}{\sqrt{3} \sqrt [3]{b}}-\frac{7}{5} a x \sqrt [3]{a+b x^3}-\frac{1}{5} x \left (a+b x^3\right )^{4/3} \]

[Out]

(-7*a*x*(a + b*x^3)^(1/3))/5 - (x*(a + b*x^3)^(4/3))/5 - (4*2^(1/3)*a^(5/3)*ArcTan[(1 - (2*2^(1/3)*(a^(1/3) +
b^(1/3)*x))/(a + b*x^3)^(1/3))/Sqrt[3]])/(Sqrt[3]*b^(1/3)) - (2*2^(1/3)*a^(5/3)*ArcTan[(1 + (2^(1/3)*(a^(1/3)
+ b^(1/3)*x))/(a + b*x^3)^(1/3))/Sqrt[3]])/(Sqrt[3]*b^(1/3)) - (7*a^2*x*(1 + (b*x^3)/a)^(2/3)*Hypergeometric2F
1[1/3, 2/3, 4/3, -((b*x^3)/a)])/(5*(a + b*x^3)^(2/3)) - (2*2^(1/3)*a^(5/3)*Log[2^(2/3) - (a^(1/3) + b^(1/3)*x)
/(a + b*x^3)^(1/3)])/(3*b^(1/3)) + (2*2^(1/3)*a^(5/3)*Log[1 + (2^(2/3)*(a^(1/3) + b^(1/3)*x)^2)/(a + b*x^3)^(2
/3) - (2^(1/3)*(a^(1/3) + b^(1/3)*x))/(a + b*x^3)^(1/3)])/(3*b^(1/3)) - (4*2^(1/3)*a^(5/3)*Log[1 + (2^(1/3)*(a
^(1/3) + b^(1/3)*x))/(a + b*x^3)^(1/3)])/(3*b^(1/3)) + (2^(1/3)*a^(5/3)*Log[2*2^(1/3) + (a^(1/3) + b^(1/3)*x)^
2/(a + b*x^3)^(2/3) + (2^(2/3)*(a^(1/3) + b^(1/3)*x))/(a + b*x^3)^(1/3)])/(3*b^(1/3))

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Rubi [C]  time = 0.0278397, antiderivative size = 56, normalized size of antiderivative = 0.12, number of steps used = 2, number of rules used = 2, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.091, Rules used = {430, 429} \[ \frac{a x \sqrt [3]{a+b x^3} F_1\left (\frac{1}{3};1,-\frac{7}{3};\frac{4}{3};\frac{b x^3}{a},-\frac{b x^3}{a}\right )}{\sqrt [3]{\frac{b x^3}{a}+1}} \]

Warning: Unable to verify antiderivative.

[In]

Int[(a + b*x^3)^(7/3)/(a - b*x^3),x]

[Out]

(a*x*(a + b*x^3)^(1/3)*AppellF1[1/3, 1, -7/3, 4/3, (b*x^3)/a, -((b*x^3)/a)])/(1 + (b*x^3)/a)^(1/3)

Rule 430

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Dist[(a^IntPart[p]*(a + b*x^n)^F
racPart[p])/(1 + (b*x^n)/a)^FracPart[p], Int[(1 + (b*x^n)/a)^p*(c + d*x^n)^q, x], x] /; FreeQ[{a, b, c, d, n,
p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[n, -1] &&  !(IntegerQ[p] || GtQ[a, 0])

Rule 429

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[a^p*c^q*x*AppellF1[1/n, -p,
-q, 1 + 1/n, -((b*x^n)/a), -((d*x^n)/c)], x] /; FreeQ[{a, b, c, d, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[n
, -1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rubi steps

\begin{align*} \int \frac{\left (a+b x^3\right )^{7/3}}{a-b x^3} \, dx &=\frac{\left (a^2 \sqrt [3]{a+b x^3}\right ) \int \frac{\left (1+\frac{b x^3}{a}\right )^{7/3}}{a-b x^3} \, dx}{\sqrt [3]{1+\frac{b x^3}{a}}}\\ &=\frac{a x \sqrt [3]{a+b x^3} F_1\left (\frac{1}{3};1,-\frac{7}{3};\frac{4}{3};\frac{b x^3}{a},-\frac{b x^3}{a}\right )}{\sqrt [3]{1+\frac{b x^3}{a}}}\\ \end{align*}

Mathematica [C]  time = 0.272522, size = 232, normalized size = 0.48 \[ \frac{4 x \left (\frac{52 a^4 F_1\left (\frac{1}{3};\frac{2}{3},1;\frac{4}{3};-\frac{b x^3}{a},\frac{b x^3}{a}\right )}{\left (a-b x^3\right ) \left (b x^3 \left (3 F_1\left (\frac{4}{3};\frac{2}{3},2;\frac{7}{3};-\frac{b x^3}{a},\frac{b x^3}{a}\right )-2 F_1\left (\frac{4}{3};\frac{5}{3},1;\frac{7}{3};-\frac{b x^3}{a},\frac{b x^3}{a}\right )\right )+4 a F_1\left (\frac{1}{3};\frac{2}{3},1;\frac{4}{3};-\frac{b x^3}{a},\frac{b x^3}{a}\right )\right )}-8 a^2-9 a b x^3-b^2 x^6\right )+27 a b x^4 \left (\frac{b x^3}{a}+1\right )^{2/3} F_1\left (\frac{4}{3};\frac{2}{3},1;\frac{7}{3};-\frac{b x^3}{a},\frac{b x^3}{a}\right )}{20 \left (a+b x^3\right )^{2/3}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(a + b*x^3)^(7/3)/(a - b*x^3),x]

[Out]

(27*a*b*x^4*(1 + (b*x^3)/a)^(2/3)*AppellF1[4/3, 2/3, 1, 7/3, -((b*x^3)/a), (b*x^3)/a] + 4*x*(-8*a^2 - 9*a*b*x^
3 - b^2*x^6 + (52*a^4*AppellF1[1/3, 2/3, 1, 4/3, -((b*x^3)/a), (b*x^3)/a])/((a - b*x^3)*(4*a*AppellF1[1/3, 2/3
, 1, 4/3, -((b*x^3)/a), (b*x^3)/a] + b*x^3*(3*AppellF1[4/3, 2/3, 2, 7/3, -((b*x^3)/a), (b*x^3)/a] - 2*AppellF1
[4/3, 5/3, 1, 7/3, -((b*x^3)/a), (b*x^3)/a])))))/(20*(a + b*x^3)^(2/3))

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Maple [F]  time = 0.592, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{-b{x}^{3}+a} \left ( b{x}^{3}+a \right ) ^{{\frac{7}{3}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^3+a)^(7/3)/(-b*x^3+a),x)

[Out]

int((b*x^3+a)^(7/3)/(-b*x^3+a),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} -\int \frac{{\left (b x^{3} + a\right )}^{\frac{7}{3}}}{b x^{3} - a}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(7/3)/(-b*x^3+a),x, algorithm="maxima")

[Out]

-integrate((b*x^3 + a)^(7/3)/(b*x^3 - a), x)

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Fricas [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(7/3)/(-b*x^3+a),x, algorithm="fricas")

[Out]

Timed out

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**3+a)**(7/3)/(-b*x**3+a),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{{\left (b x^{3} + a\right )}^{\frac{7}{3}}}{b x^{3} - a}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a)^(7/3)/(-b*x^3+a),x, algorithm="giac")

[Out]

integrate(-(b*x^3 + a)^(7/3)/(b*x^3 - a), x)